15Example: Addition method
Step 2: Removing one variable
III2v−2v++1.5m2m==150−10
Now both equations have both the unknowns and the numbers below each other.
The signs of v are different, so you add the equations.
+III′2v−2v0+++1.5m2m3.5m===150−10140
Now there is only one variable left!
Step 3: Determine the values of the two variables
First solve the equation from step 2
0+3.5mm==14040∣:3.5
Substitute m into one of the two equations
For example, m substituted into II:
v−2v−2v===40+34345∣+2
So again, the mother is 40 years old and the father is 45 years old!
L={(m∣v)=(40∣45)}.