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Introduction: Systems of Linear Equations - Part 2

15Example: Addition method

Step 2: Removing one variable

I2v+1.5m=150II2v+2m=10\def\arraystretch{1.25} \begin{array}{lrcccll}\mathrm{I}&2v& +&1.5m &=& 150 \\\mathrm{II} &-2v&+&2m &=&-10\end{array}

Now both equations have both the unknowns and the numbers below each other.

The signs of vv are different, so you add the equations.

I2v+1.5m=150+II2v+2m=100+3.5m=140\def\arraystretch{1.25} \begin{array}{llrcclr}&\mathrm{I} & 2v&+& 1.5m&=&150\\+&\mathrm{II}' & -2v&+&2m&=&-10\\\hline& & \color{#009900}0&+&3.5m&=& 140\end{array}

Now there is only one variable left!

Step 3: Determine the values of the two variables

First solve the equation from step 2

0+3.5m=140:3.5m=40\def\arraystretch{1.25} \begin{array}{rrcll}0+ 3.5m&=&140 &\qquad |:3.5\\\color{#cc0000}{m}&=&\color{#cc0000}{40}\end{array}

Substitute mm into one of the two equations

For example, mm substituted into II\mathrm{II}:

v2=40+3v2=43+2v=45\def\arraystretch{1.25} \begin{array}{rcll}v-2&=&\color{#cc0000}{40}+3\\v-2&=&43 &\qquad|+2\\\color{#009999}{v}&=&\color{#009999}{45}\end{array}

So again, the mother is 40 years old and the father is 45 years old!

L={(mv)=(4045)}\mathbb{L}=\{(m|v)=( \color{#cc0000}{40}| \color{#009999}{45})\}.


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