The parameter $mm$ is the slope of the line. The parameter $tt$ is the $yy$-axis intercept.

Line $gg$:

$y=m_{g}x+t_{g}y=m\_gx+t\_g$

The line $gg$ has slope $-\frac{3}{2}-\backslash frac\{3\}\{2\}$, so $m_g=-\frac{3}{2}m\_g\; =\; -\backslash frac\{3\}\{2\}$.

$y=-\frac{3}{2}x+t_{g}y=-\backslash frac\{3\}\{2\}x+t\_g$

It intersects the $yy$-axis at $\frac{9}{2}\backslash frac\{9\}\{2\}$, so $t_g=\frac{9}{2}t\_g\; =\; \backslash frac\{9\}\{2\}$.

$y=-\frac{3}{2}x+\frac{9}{2}y=-\backslash frac\{3\}\{2\}x+\backslash frac\{9\}\{2\}$

Line $hh$:

$y=m_{h}x+t_{h}y=m\_hx+t\_h$

The line $hh$ has slope $22$, so $m_g=-\frac{3}{2}m\_g\; =\; -\backslash frac\{3\}\{2\}$ $m_h=2m\_h\; =\; 2$

$y=2x+t_{h}y=2x+t\_h$

It intersects the $yy$-axis at $11$, so $t_h=1t\_h\; =\; 1$.

$y=2x+1y=2x+1$

Reading off the intersection point

From the plot, we may read off the intersection point $\text{SP}(1\mathrm{\mid }3)\backslash text\{SP\}(1|3)$ .