Choose any point on the line, e.g. the $yy$-axis-intercept $(0\mathrm{\mid }1)(0\backslash vert1)$, and go two to the right and three upwards, which corresponds to a slope of $m=\frac{3}{2}m=\backslash frac32$. Connect the two points to obtain a straight line.

You obtain the slope of the perpendicular (=normal) line by dividing -1 by the original slope.

Substitute $mm$ and $tt$ into the general line equation.

Choose any point on the line, e.g. the given point $P(3\mathrm{\mid }2.25)P(3|2.25)$ and go, according to the gradient $m=-\frac{2}{3}m=-\backslash frac23$ , $33$ units to the left and $22$ units upwards. Connect the two points to obtain a straight line. (see sketch in subtask 1)

Calculating the $xx$-coordinate

Set the straight line functions equal to obtain the point of intersection.

Calculating the $yy$-coordinate



Plug $xx$ into one of the line equations, e.g. that of the given line.

$\Rightarrow \backslash Rightarrow$ S$(1.5\mathrm{\mid }3.25)(1.5|3.25)$