Determining function equations.
A line has the gradient a1 and passes through the point P. Determine the equation of the function f(x), the points of intersection and draw the graph.
a1=21 P(4∣−2)
Für diese Aufgabe benötigst Du folgendes Grundwissen: Linear function
Determining the function equaition
General line equation: y=m⋅x+t
here m=a1
f(x) = a1⋅x+t ↓ plug a1=21 into the general line equation.
f(x) = 21x+t ↓ plug P into f(x)
−2 = 21⋅4+t −2 ↓ solve for t
t = −4 ↓ Plug t into f(x) .
= f(x)=21x−4
Determining the y-axis intercept
What we are looking for is the so-called y-axis intercept (here: t), i.e. where y=f(0)=0 and x=0 .
Since the general equation of a straight line is
f(x)=m⋅x+t , we have
f(0)=m⋅0+t=t.
Here t=−4
⇒ Intersection with the y-axis at (0∣−4)
Determining the x-axis intercept
f(x) = 0 ↓ We are looking for an x with f(x)=0.
21x−4 = 0 +4 21x = 4 :21 x = 214 ↓ You divide by a fraction → multiply by the reciprocal.
x = 4⋅2 x = 8 ⇒ Intersection with the x-axis at (8∣0)
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a1=43P(1∣−3)
Für diese Aufgabe benötigst Du folgendes Grundwissen: Linear function
Determining the function equation
General line equation:
f(x) = a1⋅x+t ↓ t: y-axis intercept
Plug a2=43 into the general line equation.
f(x) = 43x+t ↓ Plug P(1∣−3) into f(x) .
−3 = 43⋅1+t ↓ multiply
−3 = 43+t −43 t = −3−43 ↓ add
t = −3.75 ↓ Plug t into f(x) .
= f(x)=43x−3.75
Determining the axis intercepts
Set f(x)=0, to obtain the zeros of the function.
43x−3.75 = 0 +3.75 43x = 3.75 :43 x = 3.75:43 ↓ You divide by a fraction → multiply by the reciprocal.
x = 3.75⋅34 ↓ multiply
x = 5 Intersection with the x-axis at (5∣0)
The y-axis intercept corresponds to the point of intersection with the y-axis.
Intersection with the y-axis at (0∣−3.75)
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a1=2P(3∣−1)
Für diese Aufgabe benötigst Du folgendes Grundwissen: Linear function
Determining the function equation
General line equation: Here m=a2
f(x) = a1⋅x+t ↓ t: y-axis intercept
Plug a3=2 into the general line equation.
f(x) = 2x+t ↓ Plug P(3∣−1) into f(x) .
−1 = 2⋅3+t ↓ multiply
−1 = 6+t −6 t = −1−6 ↓ subtract
t = −7 ↓ Plug t into f(x) .
= f(x)=2x−7
Determining the axis intercepts
Set f(x)=0, to obtain the zeros of the function.
2x−7 = 0 +7 2x = 7 :2 x = 7:2 ↓ divide
x = 3.5 ⇒ Intersection with the x-axis at (27∣0).
The y-axis intercept corresponds to the point of intersection with the y-axis.
⇒ Intersection with the y-axis at (0∣−7)
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a1=54P(23∣4)
Für diese Aufgabe benötigst Du folgendes Grundwissen: Linear function
Determining the function equation
General line equation:
f(x) = a1⋅x+t ↓ t: y-axis intercept
Plug a4=54 into the general line equation
f(x) = 54x+t ↓ Plug P(23∣4) into f(x) .
4 = 54⋅23+t ↓ shorten by 2
4 = 52⋅3+t ↓ multiply
4 = 56+t −56 t = 4−56 ↓ Write 4 as a fraction with a 4 in the denominator
t = 520−56 ↓ subtract
t = 514 t = 2.8 ↓ Setze t in f(x) ein.
f(x)=54x+2.8
Determining the axis intercepts
Set f(x)=0, to obtain the zeros of the function.
54x+2.8 = 0 −2.8 54x = −2.8 :54 x = −2.8:54 ↓ divide
x = −27 x = −3.5 ⇒ Intersection with the x-axis at (−27∣0)
The y-axis intercept corresponds to the point of intersection with the y-axis.
Here t=2.8=514
⇒ Intersection with the y-axis at (0∣514).
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