Exercises: Distances, parallel and perpendicular lines

Determine the equation of the line $g$ that is parallel to the line $h$ and passes through the point $P$ .

$h$ : $y = 3 x - 2$ ; $P (1 | 0) $

For this task you need the following basic knowledge: Slope/Gradient of a line
$y = 3 x - 2$ ; $P (1 | 0)$
For the line to be parallel to $h$ , it must have the same slope.
The slope of a line is the variable $m$ of the general line equation.
$m = 3$
Setting up the line equation
Plug $m = 3$ and $P (1 | 0)$ into the the general line equation.
$0$ $=$ $3 \cdot 1 + t$ $- 3$
↓
solve for $t$
$t$ $=$ $- 3$
Plug $m$ and $t$ into the general line equation.
$\Rightarrow$ Line equation: $y = 3 x - 3$
$h$ : $y = x - 4$ ; $P (1 | 2) $

For this task you need the following basic knowledge: Slope/Gradient of a line
$y = x - 4$ ; $P (1 | 2)$
For the line to be parallel to $h$ , it must have the same slope.
The slope of a line is the variable $m$ of the general line equation.
$m = 1$
Setting up the line equation
Plug $m = 1$ and $P (1 | 2)$ into the the general line equation.
$2$ $=$ $1 + t$ $- 1$
↓
solve for $t$
$t$ $=$ $1$
Plug $m$ and $t$ into the general line equation.
$\Rightarrow$ Line equation: $y = x + 1$
$h$ : $y = 4 x$ ; $P (5 | 18) $

For this task you need the following basic knowledge: Slope/Gradient of a line
$y = 4 x$ ; $P (5 | 18)$
For the line to be parallel to $h$ , it must have the same slope.
The slope of a line is the variable $m$ of the general line equation.
$m = 4$
Setting up the line equation
Plug $m = 4$ and $P (5 | 18)$ into the the general line equation.
$18$ $=$ $4 \cdot 5 + t$ $- 20$
↓
solve for $t$
$t$ $=$ $- 2$
Plug $m$ and $t$ into the general line equation.
$\Rightarrow$ Line equation: $y = 4 x - 2$
$h$ : $y = - 2 x + 1$ ; $P (- 1 | 4)$

For this task you need the following basic knowledge: Slope/Gradient of a line
$y = - 2 x + 1$ ; $P (- 1 | 4)$
For the line to be parallel to $h$ , it must have the same slope.
The slope of a line is the variable $m$ of the general line equation.
$m = - 2$
Setting up the line equation
Plug $m = - 2$ and $P (- 1 | 4)$ into the the general line equation.
$4$ $=$ $- 2 \cdot (- 1) + t$ $- 2$
↓
solve for $t$
$t$ $=$ $2$
Plug $m$ and $t$ into the general line equation.
$\Rightarrow$ Line equation: $y = - 2 x + 2$

This content is licensed under
CC BY-SA 4.0 → What does that mean? serlo.org

$0$	$=$	$3 \cdot 1 + t$	$- 3$
	↓	solve for $t$
$t$	$=$	$- 3$

$2$	$=$	$1 + t$	$- 1$
	↓	solve for $t$
$t$	$=$	$1$

$18$	$=$	$4 \cdot 5 + t$	$- 20$
	↓	solve for $t$
$t$	$=$	$- 2$

$4$	$=$	$- 2 \cdot (- 1) + t$	$- 2$
	↓	solve for $t$
$t$	$=$	$2$

Exercises: Distances, parallel and perpendicular lines

Setting up the line equation

Setting up the line equation

Setting up the line equation

Setting up the line equation